3(18t+10)-3=9(7t+15)

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Solution for 3(18t+10)-3=9(7t+15) equation: 



3(18t+10)-3=9(7t+15)

We move all terms to the left:

3(18t+10)-3-(9(7t+15))=0

We multiply parentheses

54t-(9(7t+15))+30-3=0



We calculate terms in parentheses: -(9(7t+15)), so:

9(7t+15)

We multiply parentheses

63t+135

Back to the equation:

-(63t+135)



We add all the numbers together, and all the variables

54t-(63t+135)+27=0

We get rid of parentheses

54t-63t-135+27=0

We add all the numbers together, and all the variables

-9t-108=0

We move all terms containing t to the left, all other terms to the right

-9t=108

t=108/-9

t=-12

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