3(192+-32x+x2)=0

Solution for 3(192+-32x+x2)=0 equation:

3(192+-32x+x2)=0

We add all the numbers together, and all the variables

3(-32x+x^2+192+)=0

We multiply parentheses

3x^2-96x+576+=0

We add all the numbers together, and all the variables

3x^2-96x=0

a = 3; b = -96; c = 0;
Δ = b2-4ac
Δ = -962-4·3·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-96}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+96}{2*3}=\frac{192}{6}
=32
$