3(1d+10)=63

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Solution for 3(1d+10)=63 equation: 


d in (-oo:+oo)

3*(1*d+10) = 63 // - 63

3*(1*d+10)-63 = 0

3*(d+10)-63 = 0

3*(d+10)-63 = 0

3*d-33 = 0

3*d-33 = 0

3*d-33 = 0 // + 33

3*d = 33 // : 3

d = 33/3

d = 11

d = 11

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