3(1k+2)=6

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Solution for 3(1k+2)=6 equation: 


k in (-oo:+oo)

3*(1*k+2) = 6 // - 6

3*(1*k+2)-6 = 0

3*(k+2)-6 = 0

3*(k+2)-6 = 0

3*k = 0

3*k = 0

3*k = 0 // : 3

k = 0

k = 0

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