3(1m-5)+1=2(1m+1)-9

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Solution for 3(1m-5)+1=2(1m+1)-9 equation: 



3(1m-5)+1=2(1m+1)-9

We move all terms to the left:

3(1m-5)+1-(2(1m+1)-9)=0

We add all the numbers together, and all the variables

3(m-5)-(2(m+1)-9)+1=0

We multiply parentheses

3m-(2(m+1)-9)-15+1=0



We calculate terms in parentheses: -(2(m+1)-9), so:

2(m+1)-9

We multiply parentheses

2m+2-9

We add all the numbers together, and all the variables

2m-7

Back to the equation:

-(2m-7)



We add all the numbers together, and all the variables

3m-(2m-7)-14=0

We get rid of parentheses

3m-2m+7-14=0

We add all the numbers together, and all the variables

m-7=0

We move all terms containing m to the left, all other terms to the right

m=7

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