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3(1q-5)=2(1q-5)
We move all terms to the left:
3(1q-5)-(2(1q-5))=0
We add all the numbers together, and all the variables
3(q-5)-(2(q-5))=0
We multiply parentheses
3q-(2(q-5))-15=0
We calculate terms in parentheses: -(2(q-5)), so:We get rid of parentheses
2(q-5)
We multiply parentheses
2q-10
Back to the equation:
-(2q-10)
3q-2q+10-15=0
We add all the numbers together, and all the variables
q-5=0
We move all terms containing q to the left, all other terms to the right
q=5
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