3(1r+7)+6r=48

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Solution for 3(1r+7)+6r=48 equation: 



3(1r+7)+6r=48

We move all terms to the left:

3(1r+7)+6r-(48)=0

We add all the numbers together, and all the variables

3(r+7)+6r-48=0

We add all the numbers together, and all the variables

6r+3(r+7)-48=0

We multiply parentheses

6r+3r+21-48=0

We add all the numbers together, and all the variables

9r-27=0

We move all terms containing r to the left, all other terms to the right

9r=27

r=27/9

r=3

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