3(1x2)=12

Solution for 3(1x2)=12 equation:

3(1x^2)=12

We move all terms to the left:

3(1x^2)-(12)=0

a = 31; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·31·(-12)
Δ = 1488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1488}=\sqrt{16*93}=\sqrt{16}*\sqrt{93}=4\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{93}}{2*31}=\frac{0-4\sqrt{93}}{62}
=-\frac{4\sqrt{93}}{62}
=-\frac{2\sqrt{93}}{31}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{93}}{2*31}=\frac{0+4\sqrt{93}}{62}
=\frac{4\sqrt{93}}{62}
=\frac{2\sqrt{93}}{31}
$