3(1y+2)+1y=15-(1y+4)

Solution for 3(1y+2)+1y=15-(1y+4) equation:

Simplifying
3(1y + 2) + 1y = 15 + -1(1y + 4)

Reorder the terms:
3(2 + 1y) + 1y = 15 + -1(1y + 4)
(2 * 3 + 1y * 3) + 1y = 15 + -1(1y + 4)
(6 + 3y) + 1y = 15 + -1(1y + 4)

Combine like terms: 3y + 1y = 4y
6 + 4y = 15 + -1(1y + 4)

Reorder the terms:
6 + 4y = 15 + -1(4 + 1y)
6 + 4y = 15 + (4 * -1 + 1y * -1)
6 + 4y = 15 + (-4 + -1y)

Combine like terms: 15 + -4 = 11
6 + 4y = 11 + -1y

Solving
6 + 4y = 11 + -1y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add 'y' to each side of the equation.
6 + 4y + y = 11 + -1y + y

Combine like terms: 4y + y = 5y
6 + 5y = 11 + -1y + y

Combine like terms: -1y + y = 0
6 + 5y = 11 + 0
6 + 5y = 11

Add '-6' to each side of the equation.
6 + -6 + 5y = 11 + -6

Combine like terms: 6 + -6 = 0
0 + 5y = 11 + -6
5y = 11 + -6

Combine like terms: 11 + -6 = 5
5y = 5

Divide each side by '5'.
y = 1

Simplifying
y = 1