3(2(-0.5)+1)-2((-0.5)-2)=5

Solution for 3(2(-0.5)+1)-2((-0.5)-2)=5 equation:

Simplifying
3(2(-0.5) + 1) + -2((-0.5) + -2) = 5

Multiply 2 * -0.5
3(-1 + 1) + -2((-0.5) + -2) = 5

Combine like terms: -1 + 1 = 0
3(0) + -2((-0.5) + -2) = 5

Multiply 3 * 0
0 + -2((-0.5) + -2) = 5

Anything times zero is zero.
0 + -2((-0.5) + -2) = 5
0 + -2(-0.5 + -2) = 5

Combine like terms: -0.5 + -2 = -2.5
0 + -2(-2.5) = 5

Multiply -2 * -2.5
0 + 5 = 5

Combine like terms: 0 + 5 = 5
5 = 5

Add '-5' to each side of the equation.
5 + -5 = 5 + -5

Combine like terms: 5 + -5 = 0
0 = 5 + -5

Combine like terms: 5 + -5 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.