3(2(3-2y)-1)+2y=5(3-2y)

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Solution for 3(2(3-2y)-1)+2y=5(3-2y) equation: 



3(2(3-2y)-1)+2y=5(3-2y)

We move all terms to the left:

3(2(3-2y)-1)+2y-(5(3-2y))=0

We add all the numbers together, and all the variables

3(2(-2y+3)-1)+2y-(5(-2y+3))=0

We add all the numbers together, and all the variables

2y+3(2(-2y+3)-1)-(5(-2y+3))=0



We calculate terms in parentheses: -(5(-2y+3)), so:

5(-2y+3)

We multiply parentheses

-10y+15

Back to the equation:

-(-10y+15)



We get rid of parentheses

2y+3(2(-2y+3)-1)+10y-15=0

We add all the numbers together, and all the variables

12y+3(2(-2y+3)-1)-15=0

We move all terms containing y to the left, all other terms to the right

12y+3(2(-2y+3)-1)=15

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