3(2(x-2)+3)-20=-14-3(x-30)

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Solution for 3(2(x-2)+3)-20=-14-3(x-30) equation: 



3(2(x-2)+3)-20=-14-3(x-30)

We move all terms to the left:

3(2(x-2)+3)-20-(-14-3(x-30))=0



We calculate terms in parentheses: -(-14-3(x-30)), so:

-14-3(x-30)

determiningTheFunctionDomain
-3(x-30)-14

We multiply parentheses

-3x+90-14

We add all the numbers together, and all the variables

-3x+76

Back to the equation:

-(-3x+76)



We get rid of parentheses

3(2(x-2)+3)+3x-76-20=0

We add all the numbers together, and all the variables

3x+3(2(x-2)+3)-96=0

We move all terms containing x to the left, all other terms to the right

3x+3(2(x-2)+3)=96

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