3(2)=k+12

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Solution for 3(2)=k+12 equation:



3(2)=k+12
We move all terms to the left:
3(2)-(k+12)=0
We get rid of parentheses
-k-12+32=0
We add all the numbers together, and all the variables
-1k+20=0
We move all terms containing k to the left, all other terms to the right
-k=-20
k=-20/-1
k=+20

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