3(2*0-1)+2=8*0-2*0-1

Solution for 3(2*0-1)+2=8*0-2*0-1 equation:

Simplifying
3(2 * 0 + -1) + 2 = 8 * 0 + -2 * 0 + -1

Multiply 2 * 0
3(0 + -1) + 2 = 8 * 0 + -2 * 0 + -1

Anything times zero is zero.
3(0 + -1) + 2 = 8 * 0 + -2 * 0 + -1

Combine like terms: 0 + -1 = -1
3(-1) + 2 = 8 * 0 + -2 * 0 + -1

Multiply 3 * -1
-3 + 2 = 8 * 0 + -2 * 0 + -1

Combine like terms: -3 + 2 = -1
-1 = 8 * 0 + -2 * 0 + -1

Multiply 8 * 0
-1 = 0 + -2 * 0 + -1

Anything times zero is zero.
-1 = 0 + -2 * 0 + -1

Multiply -2 * 0
-1 = 0 + 0 + -1

Anything times zero is zero.
-1 = 0 + 0 + -1

Combine like terms: 0 + 0 = 0
-1 = 0 + -1
-1 = -1

Add '1' to each side of the equation.
-1 + 1 = -1 + 1

Combine like terms: -1 + 1 = 0
0 = -1 + 1

Combine like terms: -1 + 1 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.