3(2+2/3x)=5+2(x+1)

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Solution for 3(2+2/3x)=5+2(x+1) equation: 



3(2+2/3x)=5+2(x+1)

We move all terms to the left:

3(2+2/3x)-(5+2(x+1))=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3(2/3x+2)-(5+2(x+1))=0

We multiply parentheses

6x-(5+2(x+1))+6=0



We calculate terms in parentheses: -(5+2(x+1)), so:

5+2(x+1)

determiningTheFunctionDomain
2(x+1)+5

We multiply parentheses

2x+2+5

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We get rid of parentheses

6x-2x-7+6=0

We add all the numbers together, and all the variables

4x-1=0

We move all terms containing x to the left, all other terms to the right

4x=1

x=1/4

x=1/4

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