3(2+4y)-2(y+1)=4y+1

Solution for 3(2+4y)-2(y+1)=4y+1 equation:

Simplifying
3(2 + 4y) + -2(y + 1) = 4y + 1
(2 * 3 + 4y * 3) + -2(y + 1) = 4y + 1
(6 + 12y) + -2(y + 1) = 4y + 1

Reorder the terms:
6 + 12y + -2(1 + y) = 4y + 1
6 + 12y + (1 * -2 + y * -2) = 4y + 1
6 + 12y + (-2 + -2y) = 4y + 1

Reorder the terms:
6 + -2 + 12y + -2y = 4y + 1

Combine like terms: 6 + -2 = 4
4 + 12y + -2y = 4y + 1

Combine like terms: 12y + -2y = 10y
4 + 10y = 4y + 1

Reorder the terms:
4 + 10y = 1 + 4y

Solving
4 + 10y = 1 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
4 + 10y + -4y = 1 + 4y + -4y

Combine like terms: 10y + -4y = 6y
4 + 6y = 1 + 4y + -4y

Combine like terms: 4y + -4y = 0
4 + 6y = 1 + 0
4 + 6y = 1

Add '-4' to each side of the equation.
4 + -4 + 6y = 1 + -4

Combine like terms: 4 + -4 = 0
0 + 6y = 1 + -4
6y = 1 + -4

Combine like terms: 1 + -4 = -3
6y = -3

Divide each side by '6'.
y = -0.5

Simplifying
y = -0.5