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3(2+5)-x=4+2(x+1)
We move all terms to the left:
3(2+5)-x-(4+2(x+1))=0
We add all the numbers together, and all the variables
-x-(4+2(x+1))+37=0
We add all the numbers together, and all the variables
-1x-(4+2(x+1))+37=0
We calculate terms in parentheses: -(4+2(x+1)), so:We get rid of parentheses
4+2(x+1)
determiningTheFunctionDomain 2(x+1)+4
We multiply parentheses
2x+2+4
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
-1x-2x-6+37=0
We add all the numbers together, and all the variables
-3x+31=0
We move all terms containing x to the left, all other terms to the right
-3x=-31
x=-31/-3
x=10+1/3
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