3(2+b)*(2+b)=

Solution for 3(2+b)*(2+b)= equation:

Simplifying
3(2 + b)(2 + b) = 0

Multiply (2 + b) * (2 + b)
3(2(2 + b) + b(2 + b)) = 0
3((2 * 2 + b * 2) + b(2 + b)) = 0
3((4 + 2b) + b(2 + b)) = 0
3(4 + 2b + (2 * b + b * b)) = 0
3(4 + 2b + (2b + b2)) = 0

Combine like terms: 2b + 2b = 4b
3(4 + 4b + b2) = 0
(4 * 3 + 4b * 3 + b2 * 3) = 0
(12 + 12b + 3b2) = 0

Solving
12 + 12b + 3b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '3'.
3(4 + 4b + b2) = 0

Factor a trinomial.
3((2 + b)(2 + b)) = 0

Ignore the factor 3.
Subproblem 1
Set the factor '(2 + b)' equal to zero and attempt to solve:

Simplifying
2 + b = 0

Solving
2 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + b = 0 + -2
b = 0 + -2

Combine like terms: 0 + -2 = -2
b = -2

Simplifying
b = -2
Subproblem 2
Set the factor '(2 + b)' equal to zero and attempt to solve:

Simplifying
2 + b = 0

Solving
2 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + b = 0 + -2
b = 0 + -2

Combine like terms: 0 + -2 = -2
b = -2

Simplifying
b = -2
Solution
b = {-2, -2}