3(2+c)-4=5(c+1)+7

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Solution for 3(2+c)-4=5(c+1)+7 equation: 



3(2+c)-4=5(c+1)+7

We move all terms to the left:

3(2+c)-4-(5(c+1)+7)=0

We add all the numbers together, and all the variables

3(c+2)-(5(c+1)+7)-4=0

We multiply parentheses

3c-(5(c+1)+7)+6-4=0



We calculate terms in parentheses: -(5(c+1)+7), so:

5(c+1)+7

We multiply parentheses

5c+5+7

We add all the numbers together, and all the variables

5c+12

Back to the equation:

-(5c+12)



We add all the numbers together, and all the variables

3c-(5c+12)+2=0

We get rid of parentheses

3c-5c-12+2=0

We add all the numbers together, and all the variables

-2c-10=0

We move all terms containing c to the left, all other terms to the right

-2c=10

c=10/-2

c=-5

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