3(2+f)=4(f-2)

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Solution for 3(2+f)=4(f-2) equation: 



3(2+f)=4(f-2)

We move all terms to the left:

3(2+f)-(4(f-2))=0

We add all the numbers together, and all the variables

3(f+2)-(4(f-2))=0

We multiply parentheses

3f-(4(f-2))+6=0



We calculate terms in parentheses: -(4(f-2)), so:

4(f-2)

We multiply parentheses

4f-8

Back to the equation:

-(4f-8)



We get rid of parentheses

3f-4f+8+6=0

We add all the numbers together, and all the variables

-1f+14=0

We move all terms containing f to the left, all other terms to the right

-f=-14

f=-14/-1

f=+14

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