3(2+f)=7(f-2)

Solution for 3(2+f)=7(f-2) equation:

Simplifying
3(2 + f) = 7(f + -2)
(2 * 3 + f * 3) = 7(f + -2)
(6 + 3f) = 7(f + -2)

Reorder the terms:
6 + 3f = 7(-2 + f)
6 + 3f = (-2 * 7 + f * 7)
6 + 3f = (-14 + 7f)

Solving
6 + 3f = -14 + 7f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-7f' to each side of the equation.
6 + 3f + -7f = -14 + 7f + -7f

Combine like terms: 3f + -7f = -4f
6 + -4f = -14 + 7f + -7f

Combine like terms: 7f + -7f = 0
6 + -4f = -14 + 0
6 + -4f = -14

Add '-6' to each side of the equation.
6 + -6 + -4f = -14 + -6

Combine like terms: 6 + -6 = 0
0 + -4f = -14 + -6
-4f = -14 + -6

Combine like terms: -14 + -6 = -20
-4f = -20

Divide each side by '-4'.
f = 5

Simplifying
f = 5