3(2+k)=2(1+k)

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Solution for 3(2+k)=2(1+k) equation: 



3(2+k)=2(1+k)

We move all terms to the left:

3(2+k)-(2(1+k))=0

We add all the numbers together, and all the variables

3(k+2)-(2(k+1))=0

We multiply parentheses

3k-(2(k+1))+6=0



We calculate terms in parentheses: -(2(k+1)), so:

2(k+1)

We multiply parentheses

2k+2

Back to the equation:

-(2k+2)



We get rid of parentheses

3k-2k-2+6=0

We add all the numbers together, and all the variables

k+4=0

We move all terms containing k to the left, all other terms to the right

k=-4

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