3(2+u)-u=6+2(u+1)

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Solution for 3(2+u)-u=6+2(u+1) equation:


Simplifying
3(2 + u) + -1u = 6 + 2(u + 1)
(2 * 3 + u * 3) + -1u = 6 + 2(u + 1)
(6 + 3u) + -1u = 6 + 2(u + 1)

Combine like terms: 3u + -1u = 2u
6 + 2u = 6 + 2(u + 1)

Reorder the terms:
6 + 2u = 6 + 2(1 + u)
6 + 2u = 6 + (1 * 2 + u * 2)
6 + 2u = 6 + (2 + 2u)

Combine like terms: 6 + 2 = 8
6 + 2u = 8 + 2u

Add '-2u' to each side of the equation.
6 + 2u + -2u = 8 + 2u + -2u

Combine like terms: 2u + -2u = 0
6 + 0 = 8 + 2u + -2u
6 = 8 + 2u + -2u

Combine like terms: 2u + -2u = 0
6 = 8 + 0
6 = 8

Solving
6 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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