3(2+v)-v=4+2(v+1)

Solution for 3(2+v)-v=4+2(v+1) equation:

Simplifying
3(2 + v) + -1v = 4 + 2(v + 1)
(2 * 3 + v * 3) + -1v = 4 + 2(v + 1)
(6 + 3v) + -1v = 4 + 2(v + 1)

Combine like terms: 3v + -1v = 2v
6 + 2v = 4 + 2(v + 1)

Reorder the terms:
6 + 2v = 4 + 2(1 + v)
6 + 2v = 4 + (1 * 2 + v * 2)
6 + 2v = 4 + (2 + 2v)

Combine like terms: 4 + 2 = 6
6 + 2v = 6 + 2v

Add '-6' to each side of the equation.
6 + -6 + 2v = 6 + -6 + 2v

Combine like terms: 6 + -6 = 0
0 + 2v = 6 + -6 + 2v
2v = 6 + -6 + 2v

Combine like terms: 6 + -6 = 0
2v = 0 + 2v
2v = 2v

Add '-2v' to each side of the equation.
2v + -2v = 2v + -2v

Combine like terms: 2v + -2v = 0
0 = 2v + -2v

Combine like terms: 2v + -2v = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.