3(2+v)-v=4+2(v-1)

Solution for 3(2+v)-v=4+2(v-1) equation:

Simplifying
3(2 + v) + -1v = 4 + 2(v + -1)
(2 * 3 + v * 3) + -1v = 4 + 2(v + -1)
(6 + 3v) + -1v = 4 + 2(v + -1)

Combine like terms: 3v + -1v = 2v
6 + 2v = 4 + 2(v + -1)

Reorder the terms:
6 + 2v = 4 + 2(-1 + v)
6 + 2v = 4 + (-1 * 2 + v * 2)
6 + 2v = 4 + (-2 + 2v)

Combine like terms: 4 + -2 = 2
6 + 2v = 2 + 2v

Add '-2v' to each side of the equation.
6 + 2v + -2v = 2 + 2v + -2v

Combine like terms: 2v + -2v = 0
6 + 0 = 2 + 2v + -2v
6 = 2 + 2v + -2v

Combine like terms: 2v + -2v = 0
6 = 2 + 0
6 = 2

Solving
6 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.