3(2+w)=2(w+1)

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Solution for 3(2+w)=2(w+1) equation: 



3(2+w)=2(w+1)

We move all terms to the left:

3(2+w)-(2(w+1))=0

We add all the numbers together, and all the variables

3(w+2)-(2(w+1))=0

We multiply parentheses

3w-(2(w+1))+6=0



We calculate terms in parentheses: -(2(w+1)), so:

2(w+1)

We multiply parentheses

2w+2

Back to the equation:

-(2w+2)



We get rid of parentheses

3w-2w-2+6=0

We add all the numbers together, and all the variables

w+4=0

We move all terms containing w to the left, all other terms to the right

w=-4

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