3(2+x)+2=3-(x+1)

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Solution for 3(2+x)+2=3-(x+1) equation: 



3(2+x)+2=3-(x+1)

We move all terms to the left:

3(2+x)+2-(3-(x+1))=0

We add all the numbers together, and all the variables

3(x+2)-(3-(x+1))+2=0

We multiply parentheses

3x-(3-(x+1))+6+2=0



We calculate terms in parentheses: -(3-(x+1)), so:

3-(x+1)

determiningTheFunctionDomain
-(x+1)+3

We get rid of parentheses

-x-1+3

We add all the numbers together, and all the variables

-1x+2

Back to the equation:

-(-1x+2)



We add all the numbers together, and all the variables

3x-(-1x+2)+8=0

We get rid of parentheses

3x+1x-2+8=0

We add all the numbers together, and all the variables

4x+6=0

We move all terms containing x to the left, all other terms to the right

4x=-6

x=-6/4

x=-1+1/2

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