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3(2+x)+6/4=9
We move all terms to the left:
3(2+x)+6/4-(9)=0
determiningTheFunctionDomain 3(2+x)-9+6/4=0
We add all the numbers together, and all the variables
3(x+2)-9+6/4=0
We multiply parentheses
3x+6-9+6/4=0
We multiply all the terms by the denominator
3x*4+6+6*4-9*4=0
We add all the numbers together, and all the variables
3x*4-6=0
Wy multiply elements
12x-6=0
We move all terms containing x to the left, all other terms to the right
12x=6
x=6/12
x=1/2
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