3(2+x)-(6-7x)=13x-(1+4x)

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Solution for 3(2+x)-(6-7x)=13x-(1+4x) equation: 



3(2+x)-(6-7x)=13x-(1+4x)

We move all terms to the left:

3(2+x)-(6-7x)-(13x-(1+4x))=0

We add all the numbers together, and all the variables

3(x+2)-(-7x+6)-(13x-(4x+1))=0

We multiply parentheses

3x-(-7x+6)-(13x-(4x+1))+6=0

We get rid of parentheses

3x+7x-(13x-(4x+1))-6+6=0



We calculate terms in parentheses: -(13x-(4x+1)), so:

13x-(4x+1)

We get rid of parentheses

13x-4x-1

We add all the numbers together, and all the variables

9x-1

Back to the equation:

-(9x-1)



We add all the numbers together, and all the variables

10x-(9x-1)=0

We get rid of parentheses

10x-9x+1=0

We add all the numbers together, and all the variables

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1

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