3(2+x)-4x=x+163(2+x)-4x=x+16

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Solution for 3(2+x)-4x=x+163(2+x)-4x=x+16 equation: 



3(2+x)-4x=x+163(2+x)-4x=x+16

We move all terms to the left:

3(2+x)-4x-(x+163(2+x)-4x)=0

We add all the numbers together, and all the variables

3(x+2)-4x-(x+163(x+2)-4x)=0

We add all the numbers together, and all the variables

-4x+3(x+2)-(x+163(x+2)-4x)=0

We multiply parentheses

-4x+3x-(x+163(x+2)-4x)+6=0



We calculate terms in parentheses: -(x+163(x+2)-4x), so:

x+163(x+2)-4x

We add all the numbers together, and all the variables

-3x+163(x+2)

We multiply parentheses

-3x+163x+326

We add all the numbers together, and all the variables

160x+326

Back to the equation:

-(160x+326)



We add all the numbers together, and all the variables

-1x-(160x+326)+6=0

We get rid of parentheses

-1x-160x-326+6=0

We add all the numbers together, and all the variables

-161x-320=0

We move all terms containing x to the left, all other terms to the right

-161x=320

x=320/-161

x=-1+159/161

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