3(2+x)-x=8+2(x-1)

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Solution for 3(2+x)-x=8+2(x-1) equation: 



3(2+x)-x=8+2(x-1)

We move all terms to the left:

3(2+x)-x-(8+2(x-1))=0

We add all the numbers together, and all the variables

3(x+2)-x-(8+2(x-1))=0

We add all the numbers together, and all the variables

-1x+3(x+2)-(8+2(x-1))=0

We multiply parentheses

-1x+3x-(8+2(x-1))+6=0



We calculate terms in parentheses: -(8+2(x-1)), so:

8+2(x-1)

determiningTheFunctionDomain
2(x-1)+8

We multiply parentheses

2x-2+8

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

2x-(2x+6)+6=0

We get rid of parentheses

2x-2x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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