3(2+x)=128

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Solution for 3(2+x)=128 equation: 



3(2+x)=128

We move all terms to the left:

3(2+x)-(128)=0

We add all the numbers together, and all the variables

3(x+2)-128=0

We multiply parentheses

3x+6-128=0

We add all the numbers together, and all the variables

3x-122=0

We move all terms containing x to the left, all other terms to the right

3x=122

x=122/3

x=40+2/3

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