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3(2+x)=2(x-3)
We move all terms to the left:
3(2+x)-(2(x-3))=0
We add all the numbers together, and all the variables
3(x+2)-(2(x-3))=0
We multiply parentheses
3x-(2(x-3))+6=0
We calculate terms in parentheses: -(2(x-3)), so:We get rid of parentheses
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
3x-2x+6+6=0
We add all the numbers together, and all the variables
x+12=0
We move all terms containing x to the left, all other terms to the right
x=-12
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