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3(2+x)=4(1+x)
We move all terms to the left:
3(2+x)-(4(1+x))=0
We add all the numbers together, and all the variables
3(x+2)-(4(x+1))=0
We multiply parentheses
3x-(4(x+1))+6=0
We calculate terms in parentheses: -(4(x+1)), so:We get rid of parentheses
4(x+1)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
3x-4x-4+6=0
We add all the numbers together, and all the variables
-1x+2=0
We move all terms containing x to the left, all other terms to the right
-x=-2
x=-2/-1
x=+2
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