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3(2+x)=5(x-5)
We move all terms to the left:
3(2+x)-(5(x-5))=0
We add all the numbers together, and all the variables
3(x+2)-(5(x-5))=0
We multiply parentheses
3x-(5(x-5))+6=0
We calculate terms in parentheses: -(5(x-5)), so:We get rid of parentheses
5(x-5)
We multiply parentheses
5x-25
Back to the equation:
-(5x-25)
3x-5x+25+6=0
We add all the numbers together, and all the variables
-2x+31=0
We move all terms containing x to the left, all other terms to the right
-2x=-31
x=-31/-2
x=15+1/2
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