3(2+x)=6-4(2x-3)

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Solution for 3(2+x)=6-4(2x-3) equation: 



3(2+x)=6-4(2x-3)

We move all terms to the left:

3(2+x)-(6-4(2x-3))=0

We add all the numbers together, and all the variables

3(x+2)-(6-4(2x-3))=0

We multiply parentheses

3x-(6-4(2x-3))+6=0



We calculate terms in parentheses: -(6-4(2x-3)), so:

6-4(2x-3)

determiningTheFunctionDomain
-4(2x-3)+6

We multiply parentheses

-8x+12+6

We add all the numbers together, and all the variables

-8x+18

Back to the equation:

-(-8x+18)



We get rid of parentheses

3x+8x-18+6=0

We add all the numbers together, and all the variables

11x-12=0

We move all terms containing x to the left, all other terms to the right

11x=12

x=12/11

x=1+1/11

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