3(2+y)-y=4+2(y+1)

Solution for 3(2+y)-y=4+2(y+1) equation:

Simplifying
3(2 + y) + -1y = 4 + 2(y + 1)
(2 * 3 + y * 3) + -1y = 4 + 2(y + 1)
(6 + 3y) + -1y = 4 + 2(y + 1)

Combine like terms: 3y + -1y = 2y
6 + 2y = 4 + 2(y + 1)

Reorder the terms:
6 + 2y = 4 + 2(1 + y)
6 + 2y = 4 + (1 * 2 + y * 2)
6 + 2y = 4 + (2 + 2y)

Combine like terms: 4 + 2 = 6
6 + 2y = 6 + 2y

Add '-6' to each side of the equation.
6 + -6 + 2y = 6 + -6 + 2y

Combine like terms: 6 + -6 = 0
0 + 2y = 6 + -6 + 2y
2y = 6 + -6 + 2y

Combine like terms: 6 + -6 = 0
2y = 0 + 2y
2y = 2y

Add '-2y' to each side of the equation.
2y + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.