3(2+y)-y=6+2(y-1)

Solution for 3(2+y)-y=6+2(y-1) equation:

3(2+y)-y=6+2(y-1)

We move all terms to the left:

3(2+y)-y-(6+2(y-1))=0

We add all the numbers together, and all the variables

3(y+2)-y-(6+2(y-1))=0

We add all the numbers together, and all the variables

-1y+3(y+2)-(6+2(y-1))=0

We multiply parentheses

-1y+3y-(6+2(y-1))+6=0


We calculate terms in parentheses: -(6+2(y-1)), so:

6+2(y-1)

determiningTheFunctionDomain
2(y-1)+6

We multiply parentheses

2y-2+6

We add all the numbers together, and all the variables

2y+4

Back to the equation:

-(2y+4)


We add all the numbers together, and all the variables

2y-(2y+4)+6=0

We get rid of parentheses

2y-2y-4+6=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation