3(2+z)=-4(z-8)

Solution for 3(2+z)=-4(z-8) equation:

3(2+z)=-4(z-8)

We move all terms to the left:

3(2+z)-(-4(z-8))=0

We add all the numbers together, and all the variables

3(z+2)-(-4(z-8))=0

We multiply parentheses

3z-(-4(z-8))+6=0


We calculate terms in parentheses: -(-4(z-8)), so:

-4(z-8)

We multiply parentheses

-4z+32

Back to the equation:

-(-4z+32)


We get rid of parentheses

3z+4z-32+6=0

We add all the numbers together, and all the variables

7z-26=0

We move all terms containing z to the left, all other terms to the right

7z=26

z=26/7

z=3+5/7