3(2,2-0,3x)=2,6+(0,1x-4)

Solution for 3(2,2-0,3x)=2,6+(0,1x-4) equation:

3(2.2-0.3x)=2.6+(0.1x-4)

We move all terms to the left:

3(2.2-0.3x)-(2.6+(0.1x-4))=0

We add all the numbers together, and all the variables

3(-0.3x+2.2)-(2.6+(0.1x-4))=0

We multiply parentheses

0x-(2.6+(0.1x-4))+6.6=0


We calculate terms in parentheses: -(2.6+(0.1x-4)), so:

2.6+(0.1x-4)

determiningTheFunctionDomain
(0.1x-4)+2.6

We get rid of parentheses

0.1x-4+2.6

We add all the numbers together, and all the variables

0.1x-1.4

Back to the equation:

-(0.1x-1.4)


We add all the numbers together, and all the variables

x-(0.1x-1.4)+6.6=0

We get rid of parentheses

x-0.1x+1.4+6.6=0

We add all the numbers together, and all the variables

0.9x+8=0

We move all terms containing x to the left, all other terms to the right

0.9x=-8

x=-8/0.9

x=-8+0.8/0.9