3(2-1)-2d=4(d-2)+5

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Solution for 3(2-1)-2d=4(d-2)+5 equation: 



3(2-1)-2d=4(d-2)+5

We move all terms to the left:

3(2-1)-2d-(4(d-2)+5)=0

We add all the numbers together, and all the variables

-2d-(4(d-2)+5)+31=0



We calculate terms in parentheses: -(4(d-2)+5), so:

4(d-2)+5

We multiply parentheses

4d-8+5

We add all the numbers together, and all the variables

4d-3

Back to the equation:

-(4d-3)



We get rid of parentheses

-2d-4d+3+31=0

We add all the numbers together, and all the variables

-6d+34=0

We move all terms containing d to the left, all other terms to the right

-6d=-34

d=-34/-6

d=5+2/3

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