3(2-1)=4z+1

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Solution for 3(2-1)=4z+1 equation: 



3(2-1)=4z+1

We move all terms to the left:

3(2-1)-(4z+1)=0

We add all the numbers together, and all the variables

-(4z+1)+31=0

We get rid of parentheses

-4z-1+31=0

We add all the numbers together, and all the variables

-4z+30=0

We move all terms containing z to the left, all other terms to the right

-4z=-30

z=-30/-4

z=7+1/2

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