3(2-2)+5z=2

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Solution for 3(2-2)+5z=2 equation: 



3(2-2)+5z=2

We move all terms to the left:

3(2-2)+5z-(2)=0

determiningTheFunctionDomain
5z-2+3(2-2)=0

We add all the numbers together, and all the variables

5z-2+30=0

We add all the numbers together, and all the variables

5z+28=0

We move all terms containing z to the left, all other terms to the right

5z=-28

z=-28/5

z=-5+3/5

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