3(2-2x)=-3(x-3)-3x-3

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Solution for 3(2-2x)=-3(x-3)-3x-3 equation:



3(2-2x)=-3(x-3)-3x-3
We move all terms to the left:
3(2-2x)-(-3(x-3)-3x-3)=0
We add all the numbers together, and all the variables
3(-2x+2)-(-3(x-3)-3x-3)=0
We multiply parentheses
-6x-(-3(x-3)-3x-3)+6=0
We calculate terms in parentheses: -(-3(x-3)-3x-3), so:
-3(x-3)-3x-3
We add all the numbers together, and all the variables
-3x-3(x-3)-3
We multiply parentheses
-3x-3x+9-3
We add all the numbers together, and all the variables
-6x+6
Back to the equation:
-(-6x+6)
We get rid of parentheses
-6x+6x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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