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3(2-2x)=2(3x+1)
We move all terms to the left:
3(2-2x)-(2(3x+1))=0
We add all the numbers together, and all the variables
3(-2x+2)-(2(3x+1))=0
We multiply parentheses
-6x-(2(3x+1))+6=0
We calculate terms in parentheses: -(2(3x+1)), so:We get rid of parentheses
2(3x+1)
We multiply parentheses
6x+2
Back to the equation:
-(6x+2)
-6x-6x-2+6=0
We add all the numbers together, and all the variables
-12x+4=0
We move all terms containing x to the left, all other terms to the right
-12x=-4
x=-4/-12
x=1/3
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