3(2-2z)=9+2(z+4)

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Solution for 3(2-2z)=9+2(z+4) equation:



3(2-2z)=9+2(z+4)
We move all terms to the left:
3(2-2z)-(9+2(z+4))=0
We add all the numbers together, and all the variables
3(-2z+2)-(9+2(z+4))=0
We multiply parentheses
-6z-(9+2(z+4))+6=0
We calculate terms in parentheses: -(9+2(z+4)), so:
9+2(z+4)
determiningTheFunctionDomain 2(z+4)+9
We multiply parentheses
2z+8+9
We add all the numbers together, and all the variables
2z+17
Back to the equation:
-(2z+17)
We get rid of parentheses
-6z-2z-17+6=0
We add all the numbers together, and all the variables
-8z-11=0
We move all terms containing z to the left, all other terms to the right
-8z=11
z=11/-8
z=-1+3/8

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