3(2-3x)=-8(x-2)

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Solution for 3(2-3x)=-8(x-2) equation: 



3(2-3x)=-8(x-2)

We move all terms to the left:

3(2-3x)-(-8(x-2))=0

We add all the numbers together, and all the variables

3(-3x+2)-(-8(x-2))=0

We multiply parentheses

-9x-(-8(x-2))+6=0



We calculate terms in parentheses: -(-8(x-2)), so:

-8(x-2)

We multiply parentheses

-8x+16

Back to the equation:

-(-8x+16)



We get rid of parentheses

-9x+8x-16+6=0

We add all the numbers together, and all the variables

-1x-10=0

We move all terms containing x to the left, all other terms to the right

-x=10

x=10/-1

x=-10

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