3(2-3x)=2(3x+1)

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Solution for 3(2-3x)=2(3x+1) equation: 



3(2-3x)=2(3x+1)

We move all terms to the left:

3(2-3x)-(2(3x+1))=0

We add all the numbers together, and all the variables

3(-3x+2)-(2(3x+1))=0

We multiply parentheses

-9x-(2(3x+1))+6=0



We calculate terms in parentheses: -(2(3x+1)), so:

2(3x+1)

We multiply parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

-9x-6x-2+6=0

We add all the numbers together, and all the variables

-15x+4=0

We move all terms containing x to the left, all other terms to the right

-15x=-4

x=-4/-15

x=4/15

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