3(2-3x)=7(x+1)-33

Solution for 3(2-3x)=7(x+1)-33 equation:

3(2-3x)=7(x+1)-33

We move all terms to the left:

3(2-3x)-(7(x+1)-33)=0

We add all the numbers together, and all the variables

3(-3x+2)-(7(x+1)-33)=0

We multiply parentheses

-9x-(7(x+1)-33)+6=0


We calculate terms in parentheses: -(7(x+1)-33), so:

7(x+1)-33

We multiply parentheses

7x+7-33

We add all the numbers together, and all the variables

7x-26

Back to the equation:

-(7x-26)


We get rid of parentheses

-9x-7x+26+6=0

We add all the numbers together, and all the variables

-16x+32=0

We move all terms containing x to the left, all other terms to the right

-16x=-32

x=-32/-16

x=+2