3(2-4z)+5(z-4)=

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Solution for 3(2-4z)+5(z-4)= equation:


3(2-4z)+5(z-4)=0

We simplify the equation to the form, which is simple to understand
3(2-4z)+5(z-4)=0

Reorder the terms in parentheses
+(+6-12z)+5*(z-4)=0

Remove unnecessary parentheses
+6-12z+5+*(+z-4+)=0

Reorder the terms in parentheses
+6-12z+(+5z-20)=0

Remove unnecessary parentheses
+6-12z+5z-20=0

We move all terms containing z to the left and all other terms to the right.
-12z+5z=0-6+20

We simplify left and right side of the equation.
-7z=+14

We divide both sides of the equation by -7 to get z.
z=-2

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